Question

1. since we cannot directly measure the high - power field of view we are forced to use some ratio equations to determine the diameter. this is due to the much greater magnification under high power it is very difficult to measure the diameter of the high - power field by this method used above. simply put, viewing the ruler or grid under high power is not feasible since so little of the ruler or grid is visible and the focusing will be difficult. however, since we know the power of the objectives and the diameter of the low - power field, we can assume that: high power field diameter / low power field diameter = low power magnification / high power magnification now simply \plug in\ the appropriate numbers and you will be able to calculate the high power field diameter. using the above equation and the numbers you have previously recorded, show your work in the space below (remember to include units as necessary). answer: high power field diameter = _

Explanation:

Step1: Recall the relationship formula

The formula for the relationship between field - diameter and magnification is $\text{low power MAGNIFICATION}\times\text{low power DIAMETER}=\text{high power MAGNIFICATION}\times\text{high power DIAMETER}$. So, $\text{high power field DIAMETER}=\frac{\text{low power MAGNIFICATION}\times\text{low power DIAMETER}}{\text{high power MAGNIFICATION}}$.

Answer:

$\text{high power field DIAMETER}=\frac{\text{low power MAGNIFICATION}\times\text{low power DIAMETER}}{\text{high power MAGNIFICATION}}$