Question

solid zn is reduced from znso₄ solution. how many moles of electrons are transferred during the reduction of zn?

Explanation:

Step1: Identify the reduction half - reaction

The reduction of \(Zn^{2 + }\) (from \(ZnSO_4\), where \(Zn\) has an oxidation state of + 2) to \(Zn\) (oxidation state of 0) can be represented by the half - reaction: \(Zn^{2+}+2e^-
ightarrow Zn\).

Step2: Determine the moles of electrons transferred

From the balanced reduction half - reaction, for every 1 mole of \(Zn^{2+}\) (or \(Zn\) produced from the reduction of \(Zn^{2+}\)) that is reduced to 1 mole of \(Zn\) (s), 2 moles of electrons are transferred. This is because the \(Zn\) ion with a + 2 charge gains 2 electrons to become neutral \(Zn\) atom.

Answer:

2 moles of electrons are transferred during the reduction of \(Zn\) (from \(Zn^{2+}\) to \(Zn\)).