Question

1. solve for ( x ): ( 4\begin{bmatrix}x&3\\-1&2end{bmatrix}=\begin{bmatrix}20&12\\-4&8end{bmatrix} ).
2. find 5

Explanation:

Step1: Perform scalar multiplication

$4

$$\begin{bmatrix} x & 3 \\ -1 & 2 \end{bmatrix}$$

=

$$\begin{bmatrix} 4x & 12 \\ -4 & 8 \end{bmatrix}$$

$

Step2: Equate corresponding entries

Set $4x = 20$

Step3: Solve for x

$x = \frac{20}{4}$

Answer:

$x = 5$