Question

solve.\
-9x - 4y = 11\
-10x - 6y = 20\
(\square, \square)\
submit

Explanation:

Step1: Eliminate one variable (e.g., y)

Multiply the first equation by 3: \(3(-9x - 4y)=3\times11\) → \(-27x - 12y = 33\)
Multiply the second equation by 2: \(2(-10x - 6y)=2\times20\) → \(-20x - 12y = 40\)

Step2: Subtract the two new equations

\((-27x - 12y)-(-20x - 12y)=33 - 40\)
Simplify: \(-27x - 12y + 20x + 12y=-7\) → \(-7x=-7\)

Step3: Solve for x

Divide both sides by -7: \(x = \frac{-7}{-7}=1\)

Step4: Substitute x=1 into the first equation

\(-9(1)-4y = 11\) → \(-9 - 4y = 11\)

Step5: Solve for y

Add 9 to both sides: \(-4y = 11 + 9 = 20\)
Divide by -4: \(y=\frac{20}{-4}=-5\)

Answer:

\((1, -5)\)