Question

1. solve: 11x - 8x - 2 = 10

a. 3 b. 2 c. 4 d. 23

1. solve: 11x - 6x - 9 = 16

a. -1 b. -1 c. 5 d.

1. solve: 9x + 7 ≤ -20

a. x ≤ -3 b. x ≥ -3 c. x ≤ \\(\frac{1}{3}\\) d. x ≥ 18

1. solve: 8x + 4 ≥ -4

a. x ≥ -1 b. x ≤ -\\(\frac{1}{2}\\) c. x ≥ -\\(\frac{1}{2}\\) d. x ≥ 0

1. which equation is true when the value of x is -17?

a. 2x - 9 = 25 b. 15 - x = -2
c. 13 - 2x = -25 d. 3x + 19 = -32

1. ella has to read a book for her class. the book has 300 pages. so far ella has read 216 pages. what percentage of the total number of pages has ella read?

a. 28% b. 36% c. 52% d. 72%

1. fifty people who watch television were randomly polled as to which type of program they preferred. the results are shown in the table.

television survey

type of show	number who watch
documentary	9
drama	12
musical	8
news	5

what percent of those surveyed preferred to watch comedy shows?
a. 40% b. 32% c. 24% d. 12%

1. what percent of those surveyed preferred to watch news programs?

a. 10% b. 16% c. 20% d. 24%

Explanation:

Question 3: Solve \( 9x + 7 \leq -20 \)

Step 1: Subtract 7 from both sides

To isolate the term with \( x \), we subtract 7 from both sides of the inequality.
\( 9x + 7 - 7 \leq -20 - 7 \)
\( 9x \leq -27 \)

Step 2: Divide both sides by 9

To solve for \( x \), we divide both sides of the inequality by 9. Since 9 is positive, the direction of the inequality sign remains the same.
\( \frac{9x}{9} \leq \frac{-27}{9} \)
\( x \leq -3 \) Wait, but the option A is \( x \leq -3 \)? Wait, the original options: A. \( x \leq -3 \), B. \( x \geq -3 \), C. \( x \leq \frac{7}{9} \), D. \( x \geq 18 \). So the correct answer should be A.

Step 1: Subtract 4 from both sides

To isolate the term with \( x \), we subtract 4 from both sides of the inequality.
\( 8x + 4 - 4 \geq -4 - 4 \)
\( 8x \geq -8 \)

Step 2: Divide both sides by 8

To solve for \( x \), we divide both sides of the inequality by 8. Since 8 is positive, the direction of the inequality sign remains the same.
\( \frac{8x}{8} \geq \frac{-8}{8} \)
\( x \geq -1 \)
Which matches option A.

Step 1: Check Option A

Substitute \( x=-17 \) into \( 2x - 9 \): \( 2\times(-17)-9=-34 - 9=-43
eq25 \)

Step 2: Check Option B

Substitute \( x = -17 \) into \( 15 - x \): \( 15-(-17)=15 + 17 = 32
eq - 2 \)

Step 3: Check Option C

Substitute \( x=-17 \) into \( 13 - 2x \): \( 13-2\times(-17)=13 + 34 = 47
eq - 25 \)

Step 4: Check Option D

Substitute \( x=-17 \) into \( 3x + 19 \): \( 3\times(-17)+19=-51 + 19=-32 \)

Answer:

A. \( x \leq -3 \)

Question 4: Solve \( 8x + 4 \geq -4 \)