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solve for c. 18 < \\frac{c}{-10} + 17

Question

solve for c. 18 < \frac{c}{-10} + 17

Explanation:

Step1: Subtract 17 from both sides

$18 - 17 < \frac{c}{-10} + 17 - 17$
$1 < \frac{c}{-10}$

Step2: Multiply by -10, reverse inequality

$1 \times (-10) > \frac{c}{-10} \times (-10)$
$-10 > c$

Answer:

$c < -10$