QUESTION IMAGE
Question
solve for x.
9(x + 1) = 25 + x
\bigcirc\\ x = 2
\bigcirc\\ x = 3
\bigcirc\\ x = 4
\bigcirc\\ x = 5
Step1: Expand the left side
Using the distributive property \(a(b + c)=ab+ac\), we expand \(9(x + 1)\) to get \(9x+9\). So the equation becomes \(9x + 9=25 + x\).
Step2: Subtract \(x\) from both sides
Subtract \(x\) from each side of the equation: \(9x - x+9=25 + x - x\), which simplifies to \(8x+9 = 25\).
Step3: Subtract 9 from both sides
Subtract 9 from both sides: \(8x+9 - 9=25 - 9\), so \(8x=16\).
Step4: Divide by 8
Divide both sides by 8: \(\frac{8x}{8}=\frac{16}{8}\), which gives \(x = 2\). Wait, no, wait, let's check again. Wait, \(25-9 = 16\), \(8x=16\), \(x = 2\)? Wait, no, wait, let's re - solve:
Wait, original equation \(9(x + 1)=25 + x\)
Expand left side: \(9x+9=25 + x\)
Subtract \(x\) from both sides: \(9x - x+9=25+x - x\) → \(8x + 9=25\)
Subtract 9: \(8x=25 - 9=16\)
Divide by 8: \(x=\frac{16}{8}=2\)? Wait, but let's check by plugging \(x = 2\) into the original equation:
Left side: \(9(2 + 1)=9\times3 = 27\)
Right side: \(25+2=27\). Oh, right, so \(x = 2\) is correct. Wait, but earlier when I thought I made a mistake, but it's correct.
Wait, but let's check the options. The first option is \(x = 2\).
Wait, but let's do the solving again carefully:
\(9(x + 1)=25 + x\)
- Distribute 9: \(9x+9 = 25+x\)
- Subtract \(x\) from both sides: \(9x - x+9=25+x - x\) → \(8x + 9=25\)
- Subtract 9: \(8x=25 - 9=16\)
- Divide by 8: \(x = 2\)
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A. \(x = 2\)