Question

solve (v^{3}=28) where (v) is a real number. simplify your answer as much as possible. (if there is more than one solution, separate them with commas.)

Explanation:

Step1: Take cube - root of both sides

To solve the equation $v^{3}=28$ for $v$, we use the property that if $x^{n}=a$, then $x = \sqrt[n]{a}$. Here $n = 3$ and $a = 28$. So $v=\sqrt[3]{28}$. Since 28 has no perfect - cube factors, $\sqrt[3]{28}$ is already in simplest form.

Answer:

$\sqrt[3]{28}$