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solve. 6. container a has 5 ℓ of water. container b has 3125 ml less wa…

Question

solve.

  1. container a has 5 ℓ of water.

container b has 3125 ml less water than container a.
(a) what is the volume of water in container b?
(b) what is the total volume of water in both containers?
give your answer in litres and millilitres.

Explanation:

Response
Part (a)

Step 1: Convert liters to milliliters

We know that \( 1\ \text{liter} = 1000\ \text{milliliters} \), so for Container A with \( 5\ \text{liters} \), we calculate \( 5\times1000 = 5000\ \text{ml} \).

Step 2: Find volume in Container B

Container B has \( 3125\ \text{ml} \) less than Container A. So we subtract: \( 5000 - 3125 = 1875\ \text{ml} \). To convert back to liters and milliliters, we know \( 1875\ \text{ml}=1\ \text{liter}\ 875\ \text{milliliters} \) (since \( 1875\div1000 = 1\) with a remainder of \( 875 \)).

Step 1: Volume of Container A in ml

Container A has \( 5\ \text{liters} = 5\times1000 = 5000\ \text{ml} \).

Step 2: Volume of Container B in ml

From part (a), Container B has \( 1875\ \text{ml} \).

Step 3: Total volume in ml

Add the volumes: \( 5000 + 1875 = 6875\ \text{ml} \). Convert to liters and milliliters: \( 6875\div1000 = 6\) with a remainder of \( 875 \), so it's \( 6\ \text{liters}\ 875\ \text{milliliters} \).

Answer:

The volume of water in Container B is \( 1\ \text{liter}\ 875\ \text{milliliters} \) (or \( 1875\ \text{ml} \)).

Part (b)