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Question
solve for x in the equation $-\frac{3}{6}x + \frac{1}{6} = -\frac{2}{6}$. $x = \square$
Step1: Subtract 1/6 from both sides
$-\frac{3}{6}x + \frac{1}{6} - \frac{1}{6} = -\frac{2}{6} - \frac{1}{6}$
$-\frac{3}{6}x = -\frac{3}{6}$
Step2: Simplify fractions
$-\frac{1}{2}x = -\frac{1}{2}$
Step3: Multiply both sides by -2
$x = 1$
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