Question

solve the equation. check your solution.\
$2(y - 1) = 3y - 2$\
\bigcirc \\{2\\}\
\bigcirc \\{-4\\}\
\bigcirc \\{-2\\}\
\bigcirc \\{0\\}

Explanation:

Step1: Expand left-hand side

$2(y - 1) = 2y - 2$
Equation becomes: $2y - 2 = 3y - 2$

Step2: Isolate variable terms

Subtract $2y$ from both sides:
$2y - 2 - 2y = 3y - 2 - 2y$
$-2 = y - 2$

Step3: Solve for $y$

Add 2 to both sides:
$-2 + 2 = y - 2 + 2$
$0 = y$

Step4: Verify the solution

Substitute $y=0$ into original equation:
Left-hand side: $2(0 - 1) = 2(-1) = -2$
Right-hand side: $3(0) - 2 = 0 - 2 = -2$
Both sides are equal, so solution is valid.

Answer:

O {0}