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solve the equation $x^2 + 2 = 38$ the solution(s) is/are $x = \\square$…

Question

solve the equation $x^2 + 2 = 38$
the solution(s) is/are $x = \square$
(type an exact answer, using radicals as needed. use a comma to separate answers as needed.)

Explanation:

Step1: Isolate the squared term

Subtract 2 from both sides:
$x^2 = 38 - 2$

Step2: Simplify the right-hand side

Calculate the difference:
$x^2 = 36$

Step3: Solve for x

Take square roots of both sides:
$x = \pm\sqrt{36} = \pm6$

Answer:

$6, -6$