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solve for c. first, complete the equation. $c^{2}=a^{2}+b^{2}-2ab\\cos …

Question

solve for c.
first, complete the equation.
$c^{2}=a^{2}+b^{2}-2ab\cos c$
$c^{2}=3^{2}+10^{2}-2(3)(?)\cos$
enter the side - length that belongs in the green box.

Explanation:

Step1: Identify sides in cosine - law formula

In the cosine - law formula $c^{2}=a^{2}+b^{2}-2ab\cos C$, when $a = 3$ and $b$ is the other non - unknown side, the value of $b$ corresponding to the side of length 10 should be filled in the blank.

Step2: Determine the value for the box

The value that should be in the box is 10.

Answer:

10