Question

solve the following problem and choosquestion\\(\frac{8y^2 + 4y}{2y} =\\)\\(\circ 4y + 2\\)\\(\circ 4y + 4\\)\\(\circ 6y + 2\\)\\(\circ 6y + 4\\)

Explanation:

Step1: Split the fraction

We can split the fraction \(\frac{8y^{2}+4y}{2y}\) into two separate fractions: \(\frac{8y^{2}}{2y}+\frac{4y}{2y}\).

Step2: Simplify each fraction

For the first fraction \(\frac{8y^{2}}{2y}\), we divide the coefficients and subtract the exponents of \(y\) (using the rule \(\frac{a^{m}}{a^{n}} = a^{m - n}\) for \(a
eq0\)). So, \(\frac{8}{2}y^{2 - 1}=4y\).
For the second fraction \(\frac{4y}{2y}\), the \(y\) terms cancel out (since \(y
eq0\)) and we have \(\frac{4}{2}=2\).

Step3: Combine the results

Adding the two simplified fractions together, we get \(4y + 2\).

Answer:

\(4y + 2\) (corresponding to the option "4y + 2")