Question

solve the following system of equations.
$3x - 8y = 7$
$-3x + 13y = -17$
$x = \square$
$y = \square$

Explanation:

Step1: Add the two equations

$$(3x - 8y) + (-3x + 13y) = 7 + (-17)$$
Simplify:
$$5y = -10$$

Step2: Solve for $y$

$$y = \frac{-10}{5} = -2$$

Step3: Substitute $y=-2$ into first equation

$$3x - 8(-2) = 7$$
Simplify:
$$3x + 16 = 7$$

Step4: Solve for $x$

$$3x = 7 - 16 = -9$$
$$x = \frac{-9}{3} = -3$$

Answer:

$x = -3$
$y = -2$