Question

solve $x^2 - 8x - 9 = 0$. rewrite the equation so that it is of the form $x^2 + bx = c$. $x^2 + \square x = \square$

Explanation:

Step1: Analyze the given equation

We have the quadratic equation \(x^{2}-8x - 9=0\). We want to rewrite it in the form \(x^{2}+bx = c\).

Step2: Move the constant term to the right

To get the equation in the form \(x^{2}+bx=c\), we add 9 to both sides of the equation \(x^{2}-8x - 9 = 0\).
So, \(x^{2}-8x-9 + 9=0 + 9\), which simplifies to \(x^{2}-8x=9\). Comparing with \(x^{2}+bx = c\), we have \(b=- 8\) and \(c = 9\).

Answer:

\(x^{2}+\boxed{-8}x=\boxed{9}\)