Question

solve for x. round to the nearest tenth of a degree, if necessary.
triangle gfe with right angle at f, gf = 48, ge = 60, angle at e is x degrees

Explanation:

Step1: Identify sides for angle $x$

For $\angle E = x^\circ$, opposite side $GF = 48$, hypotenuse $GE = 60$.

Step2: Use sine function definition

$\sin(x) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{48}{60}$

Step3: Simplify the ratio

$\sin(x) = 0.8$

Step4: Calculate inverse sine

$x = \arcsin(0.8)$

Step5: Compute and round value

$x \approx 53.1^\circ$

Answer:

$53.1^\circ$