Question

solve for x. round to the nearest tenth if necessary.
9
25
a. 3.2
b. 15
c. 25
d. 225

Explanation:

Step1: Apply geometric - mean theorem

Let the large right - triangle have hypotenuse \(c = 25\) and a segment of the hypotenuse \(a = 9\). If \(x\) is the length of the leg of the right - triangle, then by the geometric - mean theorem \(x^{2}=9\times(25)\).

Step2: Solve for \(x\)

\(x=\sqrt{9\times25}=\sqrt{225}=15\)

Answer:

b. 15