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Question
solve for x. round to the nearest tenth, if necessary. w 68° x 96 v u
Step1: Identify trigonometric ratio
In right - triangle $UVW$, $\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}$. Here, $\theta = 68^{\circ}$, the opposite side to $\theta$ is $96$ and the hypotenuse is $x$. So, $\sin68^{\circ}=\frac{96}{x}$.
Step2: Solve for $x$
We know that $\sin68^{\circ}\approx0.9272$. Then, $x=\frac{96}{\sin68^{\circ}}$. Substituting the value of $\sin68^{\circ}$, we get $x=\frac{96}{0.9272}\approx103.5$.
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$103.5$