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solve for x. round to the nearest tenth, if necessary. triangle with ri…

Question

solve for x. round to the nearest tenth, if necessary.
triangle with right angle at y, side ty = 77, angle at z is 68 degrees, hypotenuse tz = x

Explanation:

Step1: Identify trigonometric ratio

We have a right triangle, angle at $Z$ is $68^\circ$, side opposite to this angle is $TY=77$, and $x$ is the hypotenuse. Use sine ratio: $\sin(\theta)=\frac{\text{opposite}}{\text{hypotenuse}}$
$\sin(68^\circ)=\frac{77}{x}$

Step2: Rearrange to solve for $x$

Isolate $x$ by cross-multiplying:
$x=\frac{77}{\sin(68^\circ)}$

Step3: Calculate the value

First find $\sin(68^\circ)\approx0.9272$, then compute:
$x\approx\frac{77}{0.9272}\approx83.0$

Answer:

$83.0$