Question

solve the system of equations $2x - 2y = -14$ and $3x - y = -1$ by combining the equations.
$\square\\ (2x\\ \\ -2y\\ =-14)$
$\square\\ (3x\\ \\ -y\\ = -1)$
$\

$$\begin{array}{r}2x\\ -2y\\ = -14\\\\3x\\ -y\\ = -1\\\\\\hline\\square\\ x+\\square\\ y=\\square\\end{array}$$

$
answer attempt 1 out of 3
you must answer all questions above in order to submit.

Explanation:

Step1: Eliminate $y$ term, scale 2nd eq

Multiply $3x - y = -1$ by $-2$:
$-2(3x - y) = -2(-1) \implies -6x + 2y = 2$

Step2: Add to 1st equation

Add $2x - 2y = -14$ and $-6x + 2y = 2$:
$(2x - 6x) + (-2y + 2y) = -14 + 2$

Step3: Simplify to find result

$\frac{}{}$
$ -4x + 0y = -12$

Step4: Fill scaling coefficients

The first equation uses a multiplier of $1$, the second uses $-2$.

Answer:

Top blank boxes (multipliers): $1$, $-2$
Bottom blank boxes: $-4$, $0$, $-12$
Final solution to the system: $x=3$, $y=10$