QUESTION IMAGE
Question
solve the system by the method of your choice.\
\select the correct choice below and, if necessary, fill in the answer box to complete your choice.\bigcirc a. there is exactly one solution. the solution set is \boxed{}.\\(\text{(simplify your answer. type an ordered pair.)}\\)\bigcirc b. there are infinitely many solutions. the solution set is \\(\\{(x,y)|3x - 4y = 10\\}\\)or \\(\\{(x,y)|4x - 3y = 4\\}\\).\bigcirc c. the solution set is \\(\varnothing\\).
Step1: Eliminate a variable (e.g., y)
Multiply the first equation by 3: \( 9x - 12y = 30 \)
Multiply the second equation by 4: \( 16x - 12y = 16 \)
Step2: Subtract the equations
Subtract the first new equation from the second: \( (16x - 12y) - (9x - 12y) = 16 - 30 \)
Simplify: \( 7x = -14 \)
Step3: Solve for x
Divide both sides by 7: \( x = \frac{-14}{7} = -2 \)
Step4: Substitute x into an original equation
Use \( 3x - 4y = 10 \), substitute \( x = -2 \): \( 3(-2) - 4y = 10 \)
Simplify: \( -6 - 4y = 10 \)
Add 6 to both sides: \( -4y = 16 \)
Divide by -4: \( y = -4 \)
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A. There is exactly one solution. The solution set is \((-2, -4)\)