Question

solve for $y$.
$y^{2}+6y - 7=0$
if there is more than one solution, separate them with commas.
if there is no solution, click on
o solution\.
$y=\square$

Explanation:

Step1: Factor the quadratic equation

Find two numbers that multiply to $-7$ and add to $6$: $7$ and $-1$.
$y^2 + 6y - 7 = (y + 7)(y - 1) = 0$

Step2: Set each factor to zero

Solve for $y$ in each factor.
$y + 7 = 0 \quad \text{or} \quad y - 1 = 0$

Step3: Calculate each solution

Isolate $y$ for each equation.
$y = -7 \quad \text{or} \quad y = 1$

Answer:

$y = -7, 1$