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Question
solve. write your answer as an integer or a fraction in simplest form.
$7 = \left(\frac{1}{7}\
ight)^{2x}$
$x = \square$
Step1: Rewrite base as negative exponent
$7 = 7^{-2x}$
Step2: Equate exponents (same base)
$1 = -2x$
Step3: Solve for x
$x = \frac{1}{-2} = -\frac{1}{2}$
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$-\frac{1}{2}$