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solve for u. \\(u^{2}+2u - 24 = 0\\) write each solution as an integer,…

Question

solve for u.
\\(u^{2}+2u - 24 = 0\\)
write each solution as an integer, proper fraction, or improper fraction in simplest form. if there are multiple solutions, separate them with commas.
\\(u = \\)
submit

Explanation:

Step1: Use quadratic formula or factoring. Let's try factoring first. We need two numbers that multiply to -24 and add to 2. The numbers are 6 and -4.

So, \(u^2 + 2u - 24 = (u + 6)(u - 4) = 0\)

Step2: Set each factor equal to zero.

For \(u + 6 = 0\), we get \(u = -6\).
For \(u - 4 = 0\), we get \(u = 4\).

Answer:

-6, 4