Question

solving a quadratic equation when a ≠ 1 by completing the square
consider ( 8x^2 - 48x = -104 )
write the equation so that
a = 1, ( x^2 + square x = square )

Explanation:

Step1: Divide all terms by 8

To make the coefficient of $x^2$ equal to 1, divide every term in the equation by the leading coefficient 8.
$\frac{8x^2}{8} - \frac{48x}{8} = \frac{-104}{8}$

Step2: Simplify each term

Calculate the result of each division to get the simplified equation.
$x^2 - 6x = -13$

Answer:

The blanks are filled as follows: $\boldsymbol{-6}$ and $\boldsymbol{-13}$, so the equation is $x^2 + \boldsymbol{-6}x = \boldsymbol{-13}$