Question

solving for side lengths of right triangles
applying trigonometric ratios to estimate side lengths
rounded to the nearest tenth, what is the length of ln?
\\(\sin(20^{circ}) = \frac{ln}{8}\\)
\\((8)\sin(20^{circ}) = ln\\)
\\(ln\\)

Explanation:

Step1: Recall sine - value calculation

We know that $\sin(20^{\circ})\approx0.342$.

Step2: Calculate the length of LN

We have the equation $LN = 8\times\sin(20^{\circ})$. Substitute $\sin(20^{\circ})\approx0.342$ into it, so $LN=8\times0.342 = 2.736$.

Step3: Round to the nearest tenth

Rounding $2.736$ to the nearest tenth gives $2.7$.

Answer:

$2.7$