Question

solving a system of equations
find the solution to this system:
equation 1 ( 5x - 2y = -11 )
equation 2 ( -2x + 5y = 17 )
step 1: to create ( x )-coefficients that are additive inverses,
equation 1 can be multiplied by 2
multiplying equation 2 by (\boldsymbol{\text{dropdown}}) will create additive inverses for the ( x )-coeffic
dropdown options: 2, 5, 10
10x - 4y = -22

Explanation:

Step1: Identify target x-coefficients

Equation 1 multiplied by 2: $2\times(5x - 2y) = 2\times(-11)$ → $10x - 4y = -22$

Step2: Find multiplier for Equation 2

We need the x-coefficient of Equation 2 to be $-10$ (additive inverse of 10). Current x-coefficient: $-2$. Solve $-2\times k = -10$ → $k=\frac{-10}{-2}=5$

Answer:

5