Question

g. square roots
assignment

1. $\frac{sqrt{36}}{sqrt{6}} =$
2. $sqrt{117 - 52} =$
3. $sqrt{336} div sqrt{7} =$
4. $sqrt{4.6 \times 2.1} =$
5. $sqrt{33} + sqrt{96} - sqrt{3} =$
6. $sqrt{104 div 13} =$

Explanation:

Step1: Simplify fraction of roots

$\frac{\sqrt{36}}{\sqrt{6}} = \sqrt{\frac{36}{6}} = \sqrt{6}$

Step2: Compute inside the root first

$\sqrt{117 - 52} = \sqrt{65}$

Step3: Simplify root division

$\sqrt{336 \div 7} = \sqrt{48} = 4\sqrt{3}$

Step4: Calculate product then root

$\sqrt{4.6 \times 2.1} = \sqrt{9.66} \approx 3.11$

Step5: Simplify each root then combine

$\sqrt{33} + \sqrt{96} - \sqrt{3} = \sqrt{33} + 4\sqrt{6} - \sqrt{3}$

Step6: Compute division inside root

$\sqrt{104 \div 13} = \sqrt{8} = 2\sqrt{2}$

Answer:

1. $\sqrt{6}$
2. $\sqrt{65}$
3. $4\sqrt{3}$
4. $\approx 3.11$ (or $\sqrt{9.66}$)
5. $\sqrt{33} + 4\sqrt{6} - \sqrt{3}$
6. $2\sqrt{2}$