Question

m∠sro =
x =
10.

Explanation:

Step1: Identify angle - relationship

Assume lines $PQ$ and $NO$ are parallel. $\angle MSQ$ and $\angle SRO$ are corresponding angles. So $\angle SRO=(8x + 11)^{\circ}$ and $\angle MSQ = 73^{\circ}$, and they are equal.

Step2: Set up equation

Set up the equation $8x+11 = 73$.

Step3: Solve for x

Subtract 11 from both sides: $8x=73 - 11=62$. Then divide both sides by 8: $x=\frac{62}{8}=\frac{31}{4}=7.75$.

Step4: Find $\angle SRO$

Substitute $x = 7.75$ into the expression for $\angle SRO$. $\angle SRO=8x + 11=8\times7.75+11=62 + 11=73^{\circ}$.

Answer:

$x = 7.75$, $m\angle SRO=73^{\circ}$