Question

for a standard normal distribution, if p(z≤a)=0.7116, what is the value of p(z≥a)?
0.2116
0.2884
0.7116
0.7884

Explanation:

Step1: Recall total probability rule

The total probability of all possible outcomes in a probability distribution is 1. For a standard - normal distribution, \(P(Z\leq a)+P(Z\geq a) = 1\).

Step2: Solve for \(P(Z\geq a)\)

We know that \(P(Z\leq a)=0.7116\). So, \(P(Z\geq a)=1 - P(Z\leq a)\).
Substitute \(P(Z\leq a) = 0.7116\) into the formula: \(P(Z\geq a)=1 - 0.7116=0.2884\).

Answer:

B. 0.2884