Question

for the standard normal distribution shown on the right, find the probability of z occurring in the indicated region. click here to view page 1 of the standard normal table. click here to view page 2 of the standard normal table. the probability is . (round to four decimal places as needed.)

Explanation:

Step1: Recall standard - normal table property

The standard - normal table gives $P(Z < z)$. We want $P(Z> - 1.26)$.

Step2: Use the complement rule

We know that $P(Z > z)=1 - P(Z < z)$. For $z=-1.26$, from the standard - normal table, $P(Z < - 1.26)$ can be found. Looking up $-1.26$ in the standard - normal table, we get $P(Z < - 1.26)=0.1038$.

Step3: Calculate the required probability

$P(Z>-1.26)=1 - P(Z < - 1.26)=1 - 0.1038 = 0.8962$.

Answer:

$0.8962$