QUESTION IMAGE
Question
state the slope and the y-int. for each, then graph the line. include at least 3 points on each line.
- $y = \frac{1}{3}x + 4$
$m = \underline{\quad\quad\quad}, b = \underline{\quad\quad\quad}$
- $y = 2x - 5$
slope = $\underline{\quad\quad\quad}$, y-int. = $\underline{\quad\quad\quad}$
- $y = -\frac{1}{3}x + 3$
$m = \underline{\quad\quad\quad}, b = \underline{\quad\quad\quad}$
- $y = -\frac{5}{3}x$
slope = $\underline{\quad\quad\quad}$, y-int. = $\underline{\quad\quad\quad}$
For Problem 4: $y = \frac{1}{3}x + 4$
Step1: Identify slope ($m$)
The equation is in slope-intercept form $y=mx+b$, so $m = \frac{1}{3}$.
Step2: Identify y-intercept ($b$)
From $y=mx+b$, $b = 4$ (point $(0,4)$).
Step3: Find 2 more points
- Let $x=3$: $y = \frac{1}{3}(3) + 4 = 5$ → $(3,5)$
- Let $x=-3$: $y = \frac{1}{3}(-3) + 4 = 3$ → $(-3,3)$
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For Problem 5: $y = 2x - 5$
Step1: Identify slope
From $y=mx+b$, slope $= 2$.
Step2: Identify y-intercept
From $y=mx+b$, y-int. $= -5$ (point $(0,-5)$).
Step3: Find 2 more points
- Let $x=3$: $y = 2(3) - 5 = 1$ → $(3,1)$
- Let $x=1$: $y = 2(1) - 5 = -3$ → $(1,-3)$
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For Problem 6: $y = -\frac{1}{2}x + 3$
Step1: Identify slope ($m$)
From $y=mx+b$, $m = -\frac{1}{2}$.
Step2: Identify y-intercept ($b$)
From $y=mx+b$, $b = 3$ (point $(0,3)$).
Step3: Find 2 more points
- Let $x=2$: $y = -\frac{1}{2}(2) + 3 = 2$ → $(2,2)$
- Let $x=-2$: $y = -\frac{1}{2}(-2) + 3 = 4$ → $(-2,4)$
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For Problem 7: $y = -\frac{5}{3}x$
Step1: Identify slope
From $y=mx+b$, slope $= -\frac{5}{3}$.
Step2: Identify y-intercept
From $y=mx+b$, $b=0$ (y-int. $= 0$, point $(0,0)$).
Step3: Find 2 more points
- Let $x=3$: $y = -\frac{5}{3}(3) = -5$ → $(3,-5)$
- Let $x=-3$: $y = -\frac{5}{3}(-3) = 5$ → $(-3,5)$
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Problem 4:
Slope ($m$) = $\frac{1}{3}$, Y-intercept ($b$) = $4$
Points to graph: $(0,4)$, $(3,5)$, $(-3,3)$
Problem 5:
Slope = $2$, Y-intercept = $-5$
Points to graph: $(0,-5)$, $(3,1)$, $(1,-3)$
Problem 6:
Slope ($m$) = $-\frac{1}{2}$, Y-intercept ($b$) = $3$
Points to graph: $(0,3)$, $(2,2)$, $(-2,4)$
Problem 7:
Slope = $-\frac{5}{3}$, Y-intercept = $0$
Points to graph: $(0,0)$, $(3,-5)$, $(-3,5)$
(To graph each line: plot the three points for each equation, then draw a straight line connecting them across the coordinate grid.)