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step 1: horizontal translation left 10 units step 2: ____________ step …

Question

step 1: horizontal translation left 10 units
step 2: ____________
step 3: reflection across the x - axis
which transformation is needed in step 2 to map figure m onto figure m?
a. horizontal translation left 3 units
b. horizontal translation right 3 units
c. vertical translation down 3 units
d. vertical translation up 3 units

Explanation:

Brief Explanations
  1. First, analyze the coordinates of a key point in figure \( M \) (e.g., the top vertex). Let's assume the top vertex of \( M \) is at \( (7, 9) \). After Step 1 (horizontal translation left 10 units), its coordinate becomes \( (7 - 10, 9)=(-3, 9) \).
  2. The top vertex of \( M' \) is at \( (-2, -4) \) (after reflection over x - axis, the y - coordinate sign flips). Before reflection (Step 3), the y - coordinate of the point before reflection should be \( 4 \) (since reflection over x - axis changes \( (x,y) \) to \( (x, -y) \)). So before Step 3, the point should be \( (-2, 4) \).
  3. Now, we have the point after Step 1: \( (-3, 9) \) and the point before Step 3: \( (-2, 4) \). To get from \( (-3, 9) \) to \( (-2, 4) \), we need to move right 1 unit horizontally? Wait, no, maybe better to look at vertical change. Wait, maybe a better approach: look at the vertical position. The original figure \( M \) is above the x - axis, \( M' \) is below. After Step 1 (left 10), then we need to move down vertically to get to the position before reflection. Let's check the vertical distance. The y - coordinate of a point in \( M \) (e.g., the lower vertices) is, say, \( 5 \). After Step 1 (left 10), the y - coordinate is still \( 5 \). The lower vertices of \( M' \) (before reflection) have y - coordinate \( - 1\)? Wait, no, reflection over x - axis: if a point is \( (x,y) \) before reflection, after reflection it's \( (x, -y) \). Let's take a point from \( M \): let's say one of the lower vertices of \( M \) is at \( (6, 5) \). After Step 1 (horizontal translation left 10 units), it becomes \( (6 - 10, 5)=(-4, 5) \). The corresponding point in \( M' \) (after reflection) is at \( (-4, -1) \). So before reflection (Step 3), the point should be \( (-4, 1) \). Wait, no, reflection over x - axis: \( (x,y)\to(x, -y) \), so if after reflection it's \( (-4, -1) \), before reflection it's \( (-4, 1) \). So from \( (-4, 5) \) (after Step 1) to \( (-4, 1) \) (before Step 3), we need to move down \( 5 - 1 = 4 \)? No, maybe my point selection is wrong. Let's take the top vertex of \( M \): let's say it's at \( (7, 9) \). After Step 1 (left 10): \( (7 - 10, 9)=(-3, 9) \). The top vertex of \( M' \) (after reflection) is at \( (-2, -4) \), so before reflection (Step 3) it's \( (-2, 4) \). So from \( (-3, 9) \) to \( (-2, 4) \): horizontal change is \( -2-(-3)=1 \) (right 1), vertical change is \( 4 - 9=-5 \) (down 5). No, that's not matching options. Wait, maybe the figure \( M \) and \( M' \): let's look at the vertical translation. The options are vertical translation down 3 or up 3. Let's check the y - coordinates. The figure \( M \) is above the x - axis, \( M' \) is below. After Step 1 (left 10), then we need to move down vertically to get to the position where reflection over x - axis will map it to \( M' \). Let's see the vertical distance between the two figures. The original figure \( M \) has a lower y - coordinate (of the base) at, say, \( y = 5 \), and \( M' \) (before reflection) has a lower y - coordinate at \( y=-1 \)? No, reflection over x - axis: if we have a figure above x - axis, after reflection it's below. So Step 2 should be a vertical translation down. Let's check the options. Option C is vertical translation down 3 units. Let's verify: take a point in \( M \), say \( (6, 5) \). Step 1: left 10, becomes \( (-4, 5) \). Step 2: down 3, becomes \( (-4, 2) \). Step 3: reflect over x - axis, becomes \( (-4, -2) \). Wait, but the \( M' \) figure's point: looking at the graph, the \( M' \) figure's lower vertex is at \( (-4, -1) \)? Maybe my po…

Answer:

C. vertical translation down 3 units