Question

step to reduce the radical. $sqrt{252}$ $sqrt{63} cdot sqrt{4}$ $squaresqrt{square}$ try

Explanation:

Step1: Simplify $\sqrt{4}$

$\sqrt{4} = 2$

Step2: Factor 63 into square factor

$63 = 9 \times 7$, so $\sqrt{63} = \sqrt{9 \times 7}$

Step3: Simplify $\sqrt{9 \times 7}$

$\sqrt{9 \times 7} = \sqrt{9} \times \sqrt{7} = 3\sqrt{7}$

Step4: Multiply the simplified terms

$2 \times 3\sqrt{7} = 6\sqrt{7}$

Answer:

$6\sqrt{7}$ (the first box is 6, the second box is 7)