Question

1. a student performs an experiment with three unknown liquids and obtains the following measurements: fluid a: m = 2500 g, v = 2000 ml. fluid b: m = 872 g, v = 854 ml. fluid c: m = 900 g, v = 1100 ml. calculate the densities for each fluid and draw how the fluids would be layered if they were combined in a beaker. 2) use your density skills to find the identity of the following mystery objects. table of densities solids density g/cm³ solids density g/cm³ marble 2.56 copper 8.92 quartz 2.64 gold 19.32 diamond 3.52 platinum 21.4 you find an old coin. its mass is 26.76g and its volume is 3 cm³. while digging in the backyard, you think you have found a diamond. it has a mass of 5.28 g and a volume of 2 cm³. what is the coin made of? ______ what did you find? ____ you find a ring with a mass of 101 g. you fill a graduated cylinder with 10 ml of water. when the ring is placed in the graduated cylinder the water moves to 15 ml. what is the ring made of? ____ there is a block on your desk that acts as a paper - weight. the measurements are 3 cm by 4 cm by 6 cm. the block has a mass of 184.32 g. what is the block made of? ______

Explanation:

Step1: Recall density formula

The density formula is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass and $V$ is volume.

Step2: Calculate density of Fluid A

Given $m_A = 2160\ g$ and $V_A=2000\ ml$, then $
ho_A=\frac{m_A}{V_A}=\frac{2160\ g}{2000\ ml}=1.08\ g/ml$

Step3: Calculate density of Fluid B

Given $m_B = 872\ g$ and $V_B = 800\ ml$, then $
ho_B=\frac{m_B}{V_B}=\frac{872\ g}{800\ ml}=1.09\ g/ml$

Step4: Calculate density of Fluid C

Given $m_C = 900\ g$ and $V_C = 1000\ ml$, then $
ho_C=\frac{m_C}{V_C}=\frac{900\ g}{1000\ ml}=0.9\ g/ml$

Step5: Determine layering of fluids

The least - dense fluid will be on top and the most - dense fluid will be at the bottom. So the order from top to bottom is Fluid C, Fluid A, Fluid B.

Step6: Identify material of old coin

Given $m_{coin}=26.76\ g$ and $V_{coin}=3\ cm^3$, $
ho_{coin}=\frac{m_{coin}}{V_{coin}}=\frac{26.76\ g}{3\ cm^3}=8.92\ g/cm^3$. From the table, it is made of Copper.

Step7: Identify material of suspected diamond

Given $m_{suspected - diamond}=5.28\ g$ and $V_{suspected - diamond}=2\ cm^3$, $
ho_{suspected - diamond}=\frac{m_{suspected - diamond}}{V_{suspected - diamond}}=\frac{5.28\ g}{2\ cm^3}=2.64\ g/cm^3$. From the table, it is Quartz.

Step8: Calculate volume of ring

The volume of the ring is equal to the volume of water displaced. $V_{ring}=15\ ml - 10\ ml=5\ ml = 5\ cm^3$. Given $m_{ring}=101\ g$, $
ho_{ring}=\frac{m_{ring}}{V_{ring}}=\frac{101\ g}{5\ cm^3}=20.2\ g/cm^3$. It is Platinum.

Step9: Calculate volume of block

The volume of the block $V_{block}=3\ cm\times4\ cm\times6\ cm = 72\ cm^3$. Given $m_{block}=184.32\ g$, $
ho_{block}=\frac{m_{block}}{V_{block}}=\frac{184.32\ g}{72\ cm^3}=2.56\ g/cm^3$. It is Marble.

Answer:

Density of Fluid A: $1.08\ g/ml$
Density of Fluid B: $1.09\ g/ml$
Density of Fluid C: $0.9\ g/ml$
Fluid layering from top to bottom: Fluid C, Fluid A, Fluid B
Coin material: Copper
Suspected - diamond material: Quartz
Ring material: Platinum
Block material: Marble