Question

a student throws a baseball upwards at an angle of 60 degrees to the horizontal. the initial horizontal and vertical components are 12.5 m/s and 21.7 m/s, respectively. according to the information and diagram above, the student can maximize the horizontal displacement of the baseball by - decreasing the angle to 30 degrees. angle has no impact on the horizontal displacement. increasing the angle above 60 degrees. decreasing the angle to 45 degrees. multiple - choice 1 point

Explanation:

Step1: Recall range formula

The range formula for projectile motion is $R=\frac{v_{0}^{2}\sin2\theta}{g}$, where $R$ is the horizontal displacement, $v_{0}$ is the initial velocity, $\theta$ is the angle of projection and $g$ is the acceleration due to gravity.

Step2: Analyze for maximum range

The function $y = \sin2\theta$ has a maximum value of 1. This occurs when $2\theta = 90^{\circ}$, so $\theta=45^{\circ}$.

Answer:

Decreasing the angle to 45 degrees.