QUESTION IMAGE
Question
a students motion is captured using a motion detector and displaye shown. use the graph to answer the following questions. right is defined as positive. answers have a 5% tolerance to allow for estimation. describe the direction of travel: left describe the motion: moving at constant speed what is the distance traveled? m what is the final speed? 12 m/s
Step1: Analyze Direction
Right is positive, so left is negative direction. The motion direction is left (as given in the dropdown, assuming the graph shows position decreasing over time, indicating leftward movement).
Step2: Analyze Motion Type
If the graph (e.g., position - time graph) has a constant slope (or velocity - time graph has constant velocity), motion is at constant speed. So "Moving at constant speed" is correct.
Step3: Distance Traveled (Assuming Graph Details)
Since the problem has a 5% tolerance, but without the graph's exact data (like initial and final positions, time), we assume typical motion. If, for example, from a position - time graph with time interval \( t \) and speed \( v \), distance \( d = v\times t \). But since the final speed was incorrectly entered as 12, maybe the correct speed and time give distance. However, without the graph, we can't calculate precisely, but if we assume the motion is constant speed left, distance depends on graph. But since the question is about the process, we note the steps.
Step4: Final Speed
If motion is constant speed, final speed equals initial speed. The incorrect entry was 12, but we need to use the graph's slope (for position - time, slope is speed; for velocity - time, the value is speed). Assuming the correct speed (e.g., if from graph, speed is constant, say \( v \), then final speed is \( v \)). But since the problem's dropdowns and entries, we correct the final speed based on graph analysis.
(Note: Since the graph is not fully visible, we assume standard constant speed motion. For example, if the position - time graph has a slope of, say, 2 m/s (left, so -2 m/s velocity, but speed is 2 m/s), but the user's incorrect entry was 12. However, without the graph, we can't get exact numbers, but the process is as above.)
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- Direction of travel: Left
- Motion: Moving at constant speed
- Distance traveled: (Depends on graph, e.g., if speed \( v \) and time \( t \), \( d = v\times t \))
- Final speed: (Depends on graph, equal to constant speed, e.g., if correct speed is \( v \), then \( v \) m/s, correcting the 12 to the actual value from the graph)