Question

sulfuryl chloride is a substance used to make chemicals for killing insects. it breaks down over time into sulfur dioxide and chlorine gas. consider the following reaction: some amount of sulfuryl chloride (so₂cl₂) breaks down to produce 4 molecules of sulfur dioxide (so₂) and 4 molecules of chlorine (cl₂). complete the table below. chemical element number of atoms in the reaction o s cl during this reaction, how many molecules of sulfuryl chloride (so₂cl₂) react?

Explanation:

Part 1: Completing the table (Oxygen, Sulfur, Chlorine atoms)

Step 1: Analyze Oxygen (O) atoms

• Each \( \text{SO}_2 \) molecule has 2 O atoms. There are 4 \( \text{SO}_2 \) molecules.
• Number of O atoms: \( 4 \times 2 = 8 \)

Step 2: Analyze Sulfur (S) atoms

• Each \( \text{SO}_2 \) molecule has 1 S atom. There are 4 \( \text{SO}_2 \) molecules.
• Number of S atoms: \( 4 \times 1 = 4 \)

Step 3: Analyze Chlorine (Cl) atoms

• Each \( \text{Cl}_2 \) molecule has 2 Cl atoms. There are 4 \( \text{Cl}_2 \) molecules.
• Number of Cl atoms: \( 4 \times 2 = 8 \)

Part 2: Molecules of \( \text{SO}_2\text{Cl}_2 \) that react

Step 1: Use conservation of atoms (or balanced reaction)

• The reaction is \( \text{SO}_2\text{Cl}_2

ightarrow \text{SO}_2 + \text{Cl}_2 \) (balanced for 1 molecule of \( \text{SO}_2\text{Cl}_2 \) producing 1 \( \text{SO}_2 \) and 1 \( \text{Cl}_2 \)).

• Since we have 4 \( \text{SO}_2 \) and 4 \( \text{Cl}_2 \), the number of \( \text{SO}_2\text{Cl}_2 \) molecules is equal to the number of \( \text{SO}_2 \) (or \( \text{Cl}_2 \)) molecules, which is 4.

Final Table and Answer for Molecules

Chemical element	Number of atoms in the reaction
S	4
Cl	8

Number of \( \text{SO}_2\text{Cl}_2 \) molecules: 4

Answer:

s:

• O atoms: \( \boldsymbol{8} \)
• S atoms: \( \boldsymbol{4} \)
• Cl atoms: \( \boldsymbol{8} \)
• Molecules of \( \text{SO}_2\text{Cl}_2 \): \( \boldsymbol{4} \)