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suppose that we are studying the amount of time customers wait in line …

Question

suppose that we are studying the amount of time customers wait in line at the checkout at the gap and old navy. the average wait time at both stores is five minutes. at the gap, the standard deviation for the wait time is 2 minutes; at old navy the standard deviation for the wait time is 5 minutes. because old navy has a higher standard deviation, we know that there is more variation in the wait times at old navy. overall, wait times at old navy are select an answer from the average; wait times at the gap are select an answer near the average. select an answer more spread out less spread out question help: message instructor submit question jump to answer

Explanation:

Step1: Recall Standard Deviation Concept

Standard deviation measures the spread (variation) of data from the mean. A higher standard deviation means data points are more spread out (more variation) from the mean, and a lower standard deviation means data points are less spread out (closer to the mean).

Step2: Analyze Old Navy's Wait Times

Old Navy has a standard deviation of 5 minutes (higher than Gap's 2 minutes). So, wait times at Old Navy are more spread out from the average.

Step3: Analyze Gap's Wait Times

Gap has a lower standard deviation (2 minutes). So, wait times at the Gap are less spread out (closer) to the average.

Answer:

For the first "Select an answer" (Old Navy's wait times from average): more spread out
For the second "Select an answer" (Gap's wait times near average): less spread out