Question

a system of equations is shown.\

$$\begin{cases}2x + 3y = -9\\\\-x + 4y = 10\\end{cases}$$

\
show hints\
solve the system by substitution.\
(\square,\square)

Explanation:

Step1: Isolate $x$ in second equation

$-x + 4y = 10 \implies x = 4y - 10$

Step2: Substitute $x$ into first equation

$2(4y - 10) + 3y = -9$

Step3: Simplify to solve for $y$

$8y - 20 + 3y = -9 \implies 11y = 11 \implies y = 1$

Step4: Substitute $y=1$ into $x$ expression

$x = 4(1) - 10 = -6$

Answer:

$(-6, 1)$