Question

1. this table describes the departures of flights out of an airport for the months of june and july.

2a what percentage of the flights in july were delayed?
give your answer as a percentage, to one decimal place.
percentage of flights = 24.9%
2b what fraction of the total number of flights during the two months were ones that departed on time in june?
fraction which departed on time = enter your next step here

Explanation:

To solve this, we need the number of on - time flights in June and the total number of flights in both June and July. Since the table is not fully visible, we assume typical data (for example, if June had 500 on - time flights and total flights in June and July were 1000). But generally, the steps are:

Step 1: Find the number of on - time flights in June

Let's say from the table, the number of on - time flights in June is \(O_J\).

Step 2: Find the total number of flights in June and July

Let the number of flights in June be \(F_J\) and in July be \(F_Jul\). Then the total number of flights \(T=F_J + F_Jul\).

Step 3: Calculate the fraction

The fraction of on - time flights in June out of total flights in two months is \(\frac{O_J}{T}\)

Since the table is not provided, but assuming we have the data (for example, if on - time in June is 450, total flights in June and July is 1000, the fraction is \(\frac{450}{1000}=\frac{9}{20}\)). But we need the actual data from the table.

However, if we assume the table has the following (a common example):

Month	On - time	Delayed	Total
July	300	100	400

Step 1: Number of on - time flights in June (\(O_J\)) = 450

Step 2: Total number of flights in two months (\(T\))=600 + 400=1000

Step 3: Fraction=\(\frac{450}{1000}=\frac{9}{20} = 0.45\)

If the actual table has:

Suppose June on - time is 520, June total is 650, July total is 550. Then total flights \(T = 650+550 = 1200\)

Fraction=\(\frac{520}{1200}=\frac{13}{30}\approx0.433\)

Since the table is not given, we need the data from the table. But the general formula is \(\text{Fraction}=\frac{\text{On - time in June}}{\text{Total flights in June + Total flights in July}}\)

If we assume the table has the following (from a similar problem):

June: On - time = 480, Total June = 600; July: Total July = 500

Total flights \(T=600 + 500=1100\)

Fraction=\(\frac{480}{1100}=\frac{24}{55}\approx0.436\)

But to get the exact answer, we need the data from the table. If we assume the table is as follows (a possible case):

Month	On Time	Delayed	Total
July	350	150	500

Step 1: On - time in June (\(O_J\)) = 420

Step 2: Total flights (\(T\))=600 + 500 = 1100

Step 3: Fraction=\(\frac{420}{1100}=\frac{21}{55}\approx0.382\)

Since the table is not provided, we can't give the exact answer without the table data. But the method is to use the formula \(\text{Fraction}=\frac{\text{On - time flights in June}}{\text{Total flights in June}+\text{Total flights in July}}\)

Answer:

To solve this, we need the number of on - time flights in June and the total number of flights in both June and July. Since the table is not fully visible, we assume typical data (for example, if June had 500 on - time flights and total flights in June and July were 1000). But generally, the steps are:

Step 1: Find the number of on - time flights in June

Let's say from the table, the number of on - time flights in June is \(O_J\).

Step 2: Find the total number of flights in June and July

Let the number of flights in June be \(F_J\) and in July be \(F_Jul\). Then the total number of flights \(T=F_J + F_Jul\).

Step 3: Calculate the fraction

The fraction of on - time flights in June out of total flights in two months is \(\frac{O_J}{T}\)

Since the table is not provided, but assuming we have the data (for example, if on - time in June is 450, total flights in June and July is 1000, the fraction is \(\frac{450}{1000}=\frac{9}{20}\)). But we need the actual data from the table.

However, if we assume the table has the following (a common example):

Month	On - time	Delayed	Total
July	300	100	400

Step 1: Number of on - time flights in June (\(O_J\)) = 450

Step 2: Total number of flights in two months (\(T\))=600 + 400=1000

Step 3: Fraction=\(\frac{450}{1000}=\frac{9}{20} = 0.45\)

If the actual table has:

Suppose June on - time is 520, June total is 650, July total is 550. Then total flights \(T = 650+550 = 1200\)

Fraction=\(\frac{520}{1200}=\frac{13}{30}\approx0.433\)

Since the table is not given, we need the data from the table. But the general formula is \(\text{Fraction}=\frac{\text{On - time in June}}{\text{Total flights in June + Total flights in July}}\)

If we assume the table has the following (from a similar problem):

June: On - time = 480, Total June = 600; July: Total July = 500

Total flights \(T=600 + 500=1100\)

Fraction=\(\frac{480}{1100}=\frac{24}{55}\approx0.436\)

But to get the exact answer, we need the data from the table. If we assume the table is as follows (a possible case):

Month	On Time	Delayed	Total
July	350	150	500

Step 1: On - time in June (\(O_J\)) = 420

Step 2: Total flights (\(T\))=600 + 500 = 1100

Step 3: Fraction=\(\frac{420}{1100}=\frac{21}{55}\approx0.382\)

Since the table is not provided, we can't give the exact answer without the table data. But the method is to use the formula \(\text{Fraction}=\frac{\text{On - time flights in June}}{\text{Total flights in June}+\text{Total flights in July}}\)