Question

the table displays the scores of students on a recent exam. find the mean of the scores to the nearest 10th.

score	number of students
95	2
90	5
85	5
80	8
75	9

Explanation:

Step1: Calculate the sum of the products of scores and frequencies

Multiply each score by its frequency and sum them up.
\[ (100\times5)+(95\times2)+(90\times5)+(85\times5)+(80\times8)+(75\times9)=500 + 190+450+425+640+675 = 2880\]

Step2: Calculate the total number of students

Sum up all the frequencies.
\[5 + 2+5+5+8+9=34\]

Step3: Calculate the mean

Divide the sum of products by the total number of students.
\[\text{Mean}=\frac{2880}{34}\approx84.7\]

Answer:

84.7