QUESTION IMAGE
Question
the table shows the educational attainment of a population, expressed in millions. find the odds in favor and the odds against a randomly selected member of the population with four years (or more) of college.
| less than 4 years high school | 4 years high school only | some college (less than 4 years) | 4 years college (or more) | total | |
|---|---|---|---|---|---|
| female | 15 | 32 | 25 | 21 | 93 |
| total | 27 | 63 | 49 | 46 | 185 |
the odds, in most reduced form, in favor of selecting a member of the population with four years (or more) of college are
(simplify your answers.)
the odds, in most reduced form, against selecting a member of the population with four years (or more) of college are
(simplify your answers.)
Step1: Recall the formula for odds in - favor
The odds in favor of an event \(E\) is given by \(\frac{\text{Number of favorable outcomes}}{\text{Number of non - favorable outcomes}}\). The number of people with four years (or more) of college is \(46\) (from the table), and the number of people without four years (or more) of college is \(185 - 46=139\).
So, the odds in favor of selecting a member with four years (or more) of college is \(\frac{46}{139}\).
Step2: Recall the formula for odds against
The odds against an event \(E\) is given by \(\frac{\text{Number of non - favorable outcomes}}{\text{Number of favorable outcomes}}\).
So, the odds against selecting a member with four years (or more) of college is \(\frac{139}{46}\).
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The odds in favor: \(\frac{46}{139}\)
The odds against: \(\frac{139}{46}\)