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Question
tallulah launches a toy rocket from a platform. the height of the rocket in feet is given by $h(t)=-16t^{2}+24t + 16$ where t represents the time in seconds after launch. what is the rockets initial height?
Step1: Identify initial time
Initial time is when $t = 0$.
Step2: Substitute $t = 0$ into function
Substitute $t=0$ into $h(t)=-16t^{2}+24t + 16$. So $h(0)=-16\times0^{2}+24\times0 + 16$.
Step3: Calculate result
$h(0)=0 + 0+16=16$.
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