Question

tammy watched the cashier scan the 7 items in her shopping cart. the scanned prices were: $3.00 $2.00 $2.00 $7.00 $3.00 $9.00 $2.00 what was the mean absolute deviation of the prices of the items? if the answer is a decimal, round it to the nearest ten cents. mean absolute deviation (mad): $

Explanation:

Step1: Calculate the mean

The prices are $3, 2, 2, 7, 3, 9, 2$. The sum is $3 + 2+2 + 7+3 + 9+2=28$. There are $n = 7$ items. The mean $\bar{x}=\frac{28}{7}=4$.

Step2: Calculate the absolute - deviations

$|3 - 4|=1$, $|2 - 4| = 2$, $|2 - 4| = 2$, $|7 - 4| = 3$, $|3 - 4| = 1$, $|9 - 4| = 5$, $|2 - 4| = 2$.

Step3: Calculate the mean of the absolute - deviations

The sum of the absolute - deviations is $1+2 + 2+3+1+5+2 = 16$. The mean absolute deviation (MAD) is $\frac{16}{7}\approx2.29$. Rounding to the nearest ten - cents, the MAD is $\$2.30$.

Answer:

$2.30$