QUESTION IMAGE
Question
task #4: equations and solutions
for each of the equations below, determine whether the given value is a solution or not.
- ( x + 2 = x^2 + 4 ) at ( x = 2 )
- ( p + 2 = p^2 - 4 ) at ( p = -2 )
- ( \frac{a - 5}{a + 5} = 1 ) at ( a = 0 )
- ( \frac{5 - a}{5 + a} = -1 ) at ( a = 0 )
- ( 3(x - 8) = 3x - 8 ) at ( x = 0 )
- which, out of the numbers 0, 1, -1, 2, -2, is/are solution(s) to the equation ( 4x^2 - 4x - 5 = 2x(x + 3) - 1 )?
Step1: Substitute $x=2$ into equation 1
Left side: $2 + 2 = 4$
Right side: $2^2 + 4 = 4 + 4 = 8$
Step2: Check equality for equation 1
$4
eq 8$, so $x=2$ is not a solution.
Step3: Substitute $p=-2$ into equation 2
Left side: $-2 + 2 = 0$
Right side: $(-2)^2 - 4 = 4 - 4 = 0$
Step4: Check equality for equation 2
$0 = 0$, so $p=-2$ is a solution.
Step5: Substitute $a=0$ into equation 3
Left side: $\frac{0 - 5}{0 + 5} = \frac{-5}{5} = -1$
Right side: $1$
Step6: Check equality for equation 3
$-1
eq 1$, so $a=0$ is not a solution.
Step7: Substitute $a=0$ into equation 4
Left side: $\frac{5 - 0}{5 + 0} = \frac{5}{5} = 1$
Right side: $-1$
Step8: Check equality for equation 4
$1
eq -1$, so $a=0$ is not a solution.
Step9: Substitute $x=0$ into equation 5
Left side: $3(0 - 8) = 3(-8) = -24$
Right side: $3(0) - 8 = 0 - 8 = -8$
Step10: Check equality for equation 5
$-24
eq -8$, so $x=0$ is not a solution.
Step11: Simplify equation 6 first
Step12: Test each value in simplified equation 6
- For $x=0$: $0^2 - 5(0) - 2 = -2
eq 0$
- For $x=1$: $1^2 - 5(1) - 2 = 1 - 5 - 2 = -6
eq 0$
- For $x=-1$: $(-1)^2 - 5(-1) - 2 = 1 + 5 - 2 = 4
eq 0$
- For $x=2$: $2^2 - 5(2) - 2 = 4 - 10 - 2 = -8
eq 0$
- For $x=-2$: $(-2)^2 - 5(-2) - 2 = 4 + 10 - 2 = 12
eq 0$
None of the values satisfy the equation.
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- $x=2$ is not a solution.
- $p=-2$ is a solution.
- $a=0$ is not a solution.
- $a=0$ is not a solution.
- $x=0$ is not a solution.
- None of the numbers 0, 1, -1, 2, -2 are solutions.