QUESTION IMAGE
Question
a test was given to a group of students. the grades and gender are summarized below.
| a | b | c | total | |
|---|---|---|---|---|
| female | 19 | 7 | 2 | 28 |
| total | 31 | 23 | 13 | 67 |
if one student is chosen at random from those who took the test, find the probability that the student was male given they got a b. round answer to three decimal places.
0.239 ×
Step1: Recall conditional - probability formula
The formula for conditional probability is $P(A|B)=\frac{P(A\cap B)}{P(B)}$. In the context of this problem, let $A$ be the event that the student is male and $B$ be the event that the student got a 'B'. Then $P(A\cap B)$ is the probability that a student is male and got a 'B', and $P(B)$ is the probability that a student got a 'B'.
Step2: Calculate $P(A\cap B)$
The number of students who are male and got a 'B' is 16. The total number of students is 67. So $P(A\cap B)=\frac{16}{67}$.
Step3: Calculate $P(B)$
The number of students who got a 'B' is 23. The total number of students is 67. So $P(B)=\frac{23}{67}$.
Step4: Calculate $P(A|B)$
Using the conditional - probability formula $P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{\frac{16}{67}}{\frac{23}{67}}=\frac{16}{23}\approx0.696$.
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$0.696$