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(problem reference 5 - 1) a 60 kg cyclist turns a corner with a radius of 50 m at a speed of 20 m/s. what is magnitude of the centripetal force acting on the cyclist?
600 n
150 n
480 n
24 n

Explanation:

Step1: Recall centripetal - force formula

The formula for centripetal force is $F = \frac{mv^{2}}{r}$, where $m$ is the mass, $v$ is the velocity, and $r$ is the radius.

Step2: Substitute given values

Given $m = 60\ kg$, $v = 20\ m/s$, and $r = 50\ m$. Substitute into the formula: $F=\frac{60\times(20)^{2}}{50}$.

Step3: Calculate the value

First, calculate $(20)^{2}=400$. Then $60\times400 = 24000$. Finally, $\frac{24000}{50}=480\ N$.

Answer:

480 N