Question

there are 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature? p x v = n x r x t r = 0.0821 a 488 k b 204.6 k c 204.6 c d 22.7 k

Explanation:

Step1: Rearrange the ideal gas law formula to solve for T.

The ideal gas law is \( PV = nRT \). To solve for \( T \), we rearrange the formula to \( T=\frac{PV}{nR} \).

Step2: Substitute the given values into the formula.

We are given \( P = 5.6\space atm \), \( V = 12\space L \), \( n = 4\space mol \), and \( R = 0.0821\space \frac{L\cdot atm}{mol\cdot K} \). Substituting these values into the formula for \( T \), we get:
\( T=\frac{(5.6\space atm)(12\space L)}{(4\space mol)(0.0821\space \frac{L\cdot atm}{mol\cdot K})} \)

Step3: Calculate the numerator and the denominator.

First, calculate the numerator: \( (5.6)(12)=67.2 \).
Then, calculate the denominator: \( (4)(0.0821) = 0.3284 \).

Step4: Divide the numerator by the denominator to find T.

\( T=\frac{67.2}{0.3284}\approx204.6\space K \)

Answer:

B. 204.6 K